Introduction
A system of two linear equations in two variables appears throughout the Algebra domain, which accounts for roughly 35% of SAT Math questions. The test doesn't just ask you to solve the system for and — it sometimes asks for a combined expression like or , where a structural shortcut gets the answer in one line. This note covers three fluent methods: substitution, elimination, and structural shortcuts, plus how to confirm any answer with Desmos.
Related notes: For systems with no solution or infinitely many solutions, see Systems with No Solution or Infinitely Many Solutions. For word problems that require setting up the system from context, see Systems of Equations in Context.
Core Concept
Every system of two linear equations in two variables has a solution that satisfies both equations simultaneously. Geometrically, it is the intersection point of two lines. Three algebraic strategies reach that point:
Strategy 1 — Substitution
Best when: One equation is already solved for one variable (or is easy to solve).
Steps:
- Isolate one variable in one equation.
- Substitute that expression into the other equation.
- Solve the resulting single-variable equation.
- Back-substitute to find the second variable.
Quick illustration:
Substitute : .
Strategy 2 — Elimination (Addition/Subtraction)
Best when: The same variable has equal (or opposite) coefficients, or can be made equal by multiplying one equation by a constant.
Steps:
- Multiply one (or both) equation(s) so one variable has matching coefficients.
- Add or subtract the equations to eliminate that variable.
- Solve for the remaining variable; back-substitute.
Quick illustration:
Subtract: ; back-sub: .
Strategy 3 — Structural Shortcut
Best when: The question asks for a combined expression (e.g., , ) rather than individual values.
Key idea: Adding or subtracting the two equations often directly produces the target expression. No need to find and separately.
Quick illustration:
If the question asked for , the answer is — one step.
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