SAT · Math · Equivalent Expressions

Polynomial Operations

9 min readPreviewBy Uzair Khan

What you'll be able to do

Combining like terms, distributing negatives, multiplying binomials and larger polynomials, and matching an expanded form to the answer choices, including finding a missing coefficient.

Introduction

Polynomial operations sit squarely in the Advanced Math domain, which makes up roughly 35% of SAT Math questions. You will be asked to simplify, expand, or match an expression, often to find a specific coefficient or constant term. The skill appears in both straightforward multiple-choice questions and in student-produced response (SPR) questions, usually in 3–5 questions per test.


Core Concept

A polynomial is a sum of terms of the form axnax^n where aa is a real number and nn is a non-negative integer. Polynomial operations have three moves:

1. Adding and Subtracting — Combine Like Terms

Terms are like if they share the same variable and exponent. Add or subtract their coefficients; leave the variable part alone.

(5x2−2x+1)+(−3x2+4x−9)=(5−3)x2+(−2+4)x+(1−9)=2x2+2x−8(5x^2 - 2x + 1) + (-3x^2 + 4x - 9) = (5-3)x^2 + (-2+4)x + (1-9) = 2x^2 + 2x - 8

2. Distributing a Negative — The #1 Error Source

Subtracting a polynomial means distributing the negative to every term inside the parentheses.

(4x2+3x−1)−(x2−5x+7)=4x2+3x−1−x2+5x−7=3x2+8x−8(4x^2 + 3x - 1) - (x^2 - 5x + 7) = 4x^2 + 3x - 1 - x^2 + 5x - 7 = 3x^2 + 8x - 8

The signs of −x2-x^2, +5x+5x, and −7-7 all flipped. Miss one flip and you get a wrong answer — SAT distractors are built exactly on this error.

3. Multiplying Polynomials — Distribute Every Term

Use the distributive property: multiply each term in the first polynomial by each term in the second.

Binomial × binomial (FOIL is just a memory device for this case):

(3x−4)(2x+5)=3x⋅2x+3x⋅5+(−4)⋅2x+(−4)⋅5=6x2+15x−8x−20=6x2+7x−20(3x - 4)(2x + 5) = 3x \cdot 2x + 3x \cdot 5 + (-4) \cdot 2x + (-4) \cdot 5 = 6x^2 + 15x - 8x - 20 = 6x^2 + 7x - 20

Larger products — the same rule, more pairs:

(x2+3x−2)(x+4)(x^2 + 3x - 2)(x + 4)
=x3+4x2+3x2+12x−2x−8=x3+7x2+10x−8= x^3 + 4x^2 + 3x^2 + 12x - 2x - 8 = x^3 + 7x^2 + 10x - 8

Missing Coefficients

A common SAT format gives you an expanded form with one coefficient labeled as an unknown variable (say bb), then asks for bb. Expand the product fully, collect like terms, then match coefficients term-by-term.


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