SAT · Math · Equivalent Expressions

Factoring Polynomials

11 min readPreviewBy Uzair Khan

What you'll be able to do

Greatest common factor, difference of squares, factoring trinomials including leading coefficients other than 1, and using a factored form to answer a question.

Introduction

Factoring polynomials falls under the Advanced Math domain, which makes up roughly 35% of SAT Math questions. The skill appears in two flavors: rewrite an expression in factored form, or use a factored form to find zeros, missing constants, or equivalent simplified expressions. Every version of the test includes at least one or two questions that hinge entirely on recognizing which factoring strategy to apply and executing it cleanly.

This note covers the three strategies specified in the testing point: greatest common factor (GCF), difference of squares, and trinomial factoring (including leading coefficients other than 1). For expanding or multiplying polynomial expressions, see the Polynomial Operations note; for simplifying rational expressions with factored numerators and denominators, see Rational Expressions.


Core Concept

Factoring is the reverse of distribution. Given a polynomial, you rewrite it as a product of simpler expressions. The factored form is equivalent to the original — they produce the same output for every value of the variable — so you can substitute one for the other anywhere on the test.

Step 0 — always check for a GCF first. Even when a difference-of-squares or trinomial pattern is present, pulling out the GCF first keeps the numbers small.

Strategy 1 — Greatest Common Factor

Find the largest coefficient that divides every term AND the lowest power of each variable that appears in every term. Factor it out using the distributive property.

6x3−15x2+9x=3x(2x2−5x+3)6x^3 - 15x^2 + 9x = 3x(2x^2 - 5x + 3)

The GCF here is 3x3x: the coefficient 33 divides 6,15,96, 15, 9, and every term has at least one factor of xx.

Strategy 2 — Difference of Squares

A binomial of the form A2−B2A^2 - B^2 factors as (A−B)(A+B)(A - B)(A + B). Both terms must be perfect squares and the operation must be subtraction (a sum of squares does not factor over the reals).

4x2−25=(2x)2−52=(2x−5)(2x+5)4x^2 - 25 = (2x)^2 - 5^2 = (2x - 5)(2x + 5)

Strategy 3 — Trinomial Factoring

For ax2+bx+cax^2 + bx + c with a=1a = 1: find two numbers that multiply to cc and add to bb.

For ax2+bx+cax^2 + bx + c with a≠1a \neq 1: use the AC method — find two numbers that multiply to acac and add to bb, split the middle term, then factor by grouping.

3x2+11x+6→ac=18,  9+2=113x2+9x+2x+6=3x(x+3)+2(x+3)=(3x+2)(x+3)3x^2 + 11x + 6 \quad \xrightarrow{ac = 18,\; 9+2=11} \quad 3x^2 + 9x + 2x + 6 = 3x(x+3) + 2(x+3) = (3x+2)(x+3)

Using the factored form to answer a question

Many SAT questions don't stop at "factor this." They ask: Which value makes the expression equal zero? What is the constant kk? What is the simplified form of this fraction? Always ask yourself what the factored form tells you before writing down an answer.


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Prerequisites: Polynomial Operations

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