SAT · Math · Right Triangles and Trigonometry

The Pythagorean Theorem and Special Right Triangles

9 min readPreviewBy Uzair Khan

What you'll be able to do

A² + b² = c², common Pythagorean triples, the 45°-45°-90° and 30°-60°-90° side ratios from the reference sheet, and diagonals of rectangles and squares.

Introduction

Right triangles appear throughout the SAT's Geometry and Trigonometry domain, which makes up about 15% of the section. Whether you're finding a missing side of a triangle or the diagonal of a rectangle, three tools cover nearly every situation: the Pythagorean theorem, common Pythagorean triples, and the side ratios of the two special right triangles. This note covers exactly those tools. For using sine, cosine, and tangent in right triangles, see the sibling note Right Triangle Trigonometry.


Core Concept

The Pythagorean Theorem

For any right triangle with legs aa and bb and hypotenuse cc (the side opposite the right angle):

a2+b2=c2a^2 + b^2 = c^2

This is on the reference sheet, so you never need to memorize it — but you must apply it quickly and in both directions:

  • Finding the hypotenuse: c=a2+b2c = \sqrt{a^2 + b^2}
  • Finding a leg: a=c2−b2a = \sqrt{c^2 - b^2}

Pythagorean Triples

A Pythagorean triple is a set of three positive integers that satisfy a2+b2=c2a^2 + b^2 = c^2. Recognizing them lets you skip the arithmetic entirely. Every triple can be scaled by any positive integer.

Base triple×2×3×4×5
3-4-56-8-109-12-1512-16-2015-20-25
5-12-1310-24-2615-36-39——
8-15-1716-30-34———
7-24-2514-48-50———

If you see two sides of a right triangle that match a multiple of a known triple, the third side is determined instantly — no calculator needed.

Diagonals of Rectangles and Squares

The diagonal of a rectangle splits it into two congruent right triangles. If the rectangle has length ℓ\ell and width ww, the diagonal dd satisfies:

d=ℓ2+w2d = \sqrt{\ell^2 + w^2}

For a square with side ss, both legs are equal, so d=s2+s2=s2d = \sqrt{s^2 + s^2} = s\sqrt{2} — which is exactly the 45°-45°-90° ratio.

Special Right Triangles

Both ratios below are on the reference sheet.

45°-45°-90° (isosceles right triangle): legs ss and ss, hypotenuse s2s\sqrt{2}.

30°-60°-90°: shortest leg xx (opposite 30°), longer leg x3x\sqrt{3} (opposite 60°), hypotenuse 2x2x (opposite 90°).

The key move: identify the 30° or 45° angle, locate the side whose length you know, and set up the ratio to find the unknown.


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