SAT · Math · Area and Volume

Scale Factors: Length, Area, and Volume

9 min readPreviewBy Uzair Khan

What you'll be able to do

Similar figures and solids, and how multiplying every dimension by k changes perimeter, area, and volume.

Introduction

Scale factor questions appear in the Geometry and Trigonometry domain, which makes up about 15% of SAT Math. You'll be given two similar figures or solids and asked to connect their dimensions, areas, or volumes — or to reverse-engineer the scale factor itself. Mastering the kk, k2k^2, k3k^3 rule lets you answer these quickly, often without computing individual measurements.


Core Concept

Similar figures are identical in shape but different in size. Every corresponding length is multiplied by the same value — the scale factor kk.

The cascade of consequences is the heart of this topic:

MeasurementScales by
Any length (side, perimeter, radius, height, …)kk
Any area (base area, surface area, cross-section, …)k2k^2
Any volumek3k^3

Why? Area formulas always multiply two lengths together (e.g., A=πr2A = \pi r^2 or A=12bhA = \frac{1}{2}bh), so each gets multiplied by kk, giving k⋅k=k2k \cdot k = k^2. Volume formulas multiply three lengths (e.g., V=πr2hV = \pi r^2 h), giving k3k^3.

Quick illustration: A square has side 3, so area = 9 and perimeter = 12. Scale by k=4k = 4: new side = 12, new perimeter = 48 = 12×412 \times 4, new area = 144 = 9×16=9×429 \times 16 = 9 \times 4^2. ✓

Finding kk from given information:

  • If two lengths are given, k=new lengthoriginal lengthk = \dfrac{\text{new length}}{\text{original length}}.
  • If two areas are given, k=new areaoriginal areak = \sqrt{\dfrac{\text{new area}}{\text{original area}}}.
  • If two volumes are given, k=new volumeoriginal volume3k = \sqrt[3]{\dfrac{\text{new volume}}{\text{original volume}}}.

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