CAIE A-Level · Mathematics 9709 · Series

Sum to Infinity of a Geometric Progression

8 min readSyllabus 1.6PreviewBy Uzair Khan

Syllabus objective

Use the condition for the convergence of a geometric progression, and the formula for the sum to infinity of a convergent geometric progression.

Introduction

When the terms of a geometric progression (GP) get progressively smaller in magnitude, the sum of the series approaches a fixed, finite value — even as the number of terms grows without bound. This limiting value is called the sum to infinity. In the 9709 exam, questions on this topic appear regularly, either as standalone calculations or embedded within problems involving algebraic expressions for the first term and common ratio. Mastery requires knowing precisely when a GP converges and how to apply the sum to infinity formula efficiently.


Core Concept

Recall that for a GP with first term aa and common ratio rr, the sum of the first nn terms is:

Sn=a(1rn)1r,r1S_n = \frac{a(1 - r^n)}{1 - r}, \quad r \neq 1

Now consider what happens as nn \to \infty. The behaviour of SnS_n depends entirely on rnr^n:

  • If r<1|r| < 1, then rn0r^n \to 0 as nn \to \infty, so SnS_n approaches a finite limit.
  • If r1|r| \geq 1, then rn|r^n| does not tend to zero, so SnS_n diverges (no finite sum to infinity exists).

Convergence condition: A geometric progression converges (has a sum to infinity) if and only if r<1|r| < 1, i.e. 1<r<1-1 < r < 1.

When r<1|r| < 1, letting nn \to \infty causes the term rn0r^n \to 0, giving:

S=a1rS_\infty = \frac{a}{1 - r}

This is the sum to infinity of a convergent GP.


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Prerequisites: Sums of Progressions

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