CAIE A-Level · Mathematics 9709 · Hypothesis Tests

Hypothesis Tests for Binomial and Poisson Distributions (9709 S2 §6.5)

11 min readSyllabus 6.5PreviewBy Uzair Khan

Syllabus objective

Formulate hypotheses and carry out a hypothesis test in the context of a single observation from a population which has a binomial or Poisson distribution, using either direct evaluation of probabilities or a normal approximation to the binomial or the Poisson distribution, where appropriate.

Introduction

Hypothesis testing is one of the most heavily examined topics in Statistics 2. This subtopic builds directly on the framework introduced in §6.4 (Introduction to Hypothesis Testing) and applies it to two key discrete distributions: the Binomial and the Poisson. The core skill is to take a single observed value, calculate the probability of obtaining a result "at least as extreme" under a null hypothesis, and compare it with a stated significance level to reach a conclusion. Examiners reward precise language, correct tail identification, and an explicit comparison — every step must be shown.


Core Concept

The Hypothesis-Testing Framework

A hypothesis test for a Binomial or Poisson parameter follows five stages:

  1. State H0H_0 and H1H_1 — the null hypothesis fixes the parameter; the alternative states the direction of interest.
  2. Choose significance level α\alpha (e.g. 5%, 1%, 10%) — given in the question.
  3. Identify the critical region / compute the pp-value — using exact probabilities or a normal approximation.
  4. Compare — if p-valueαp\text{-value} \leq \alpha, reject H0H_0; otherwise do not reject H0H_0.
  5. Conclude in context — a statement referring to the original scenario.

Binomial Tests

If a random variable XB(n,p)X \sim \text{B}(n, p) under H0H_0, a single observation xx is made. The pp-value is the probability of obtaining a value at least as extreme as xx in the direction of H1H_1:

  • One-tailed (upper): H1:p>p0H_1: p > p_0p-value=P(Xx)p\text{-value} = P(X \geq x)
  • One-tailed (lower): H1:p<p0H_1: p < p_0p-value=P(Xx)p\text{-value} = P(X \leq x)
  • Two-tailed: H1:pp0H_1: p \neq p_0p-value=2×min(P(Xx),P(Xx))p\text{-value} = 2 \times \min\bigl(P(X \leq x),\, P(X \geq x)\bigr), or find both critical regions and check which tail xx falls in.

Poisson Tests

If XPo(λ)X \sim \text{Po}(\lambda) under H0H_0, the same logic applies with the Poisson probability formula:

P(X=k)=eλλkk!P(X = k) = \frac{e^{-\lambda}\lambda^k}{k!}

Cumulative Poisson probabilities are evaluated directly (or read from tables if permitted).

Normal Approximation

When nn is large and np>5np > 5 and n(1p)>5n(1-p) > 5, approximate B(n,p)\text{B}(n,p) by N(np,np(1p))\text{N}(np,\, np(1-p)).
When λ>15\lambda > 15 (approximately), approximate Po(λ)\text{Po}(\lambda) by N(λ,λ)\text{N}(\lambda, \lambda).
Apply a continuity correction in both cases.


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