CAIE A-Level · Mathematics 9709 · Continuous Random Variables

Probability Density Functions

10 min readPreviewBy Uzair Khan

What you'll be able to do

Understand the concept of a continuous random variable, and recall and use properties of a probability density function. For density functions defined over a single interval only; the domain may be infinite, e.g. f(x) = 4/x³ for x ≥ 1.

Introduction

A continuous random variable (CRV) can take any value in an interval — for example, the exact height of a randomly chosen student, or the time until a component fails. Unlike a discrete random variable, we cannot list individual probabilities for each outcome; instead, probability is described by a probability density function (PDF), which spreads probability continuously across an interval.

In the 9709 Paper 6 exam, questions on PDFs regularly ask you to verify that a function is a valid PDF, find unknown constants, and calculate probabilities as definite integrals. Mastering this topic is therefore essential for confident performance in PS2.


Core Concept

Continuous Random Variables

A continuous random variable XX takes values over an interval (which may be infinite). Individual point probabilities are always zero: P(X=a)=0P(X = a) = 0 for any specific value aa. Probability is only meaningful over an interval.

The Probability Density Function

A function f(x)f(x) is a valid probability density function for a CRV XX if and only if it satisfies two conditions:

  1. Non-negativity: f(x)≥0f(x) \geq 0 for all xx in the domain (and f(x)=0f(x) = 0 outside the domain).
  2. Total area equals 1: The integral of f(x)f(x) over the entire domain equals 1.

Probabilities are computed as areas under the curve:

P(a≤X≤b)=∫abf(x) dxP(a \leq X \leq b) = \int_a^b f(x)\, dx

Because P(X=a)=0P(X = a) = 0, it makes no difference whether the endpoints are included:

P(a≤X≤b)=P(a<X<b)=P(a≤X<b)=P(a<X≤b)P(a \leq X \leq b) = P(a < X < b) = P(a \leq X < b) = P(a < X \leq b)

Infinite Domains

The syllabus explicitly includes PDFs defined on infinite intervals, such as f(x)=4x3f(x) = \dfrac{4}{x^3} for x≥1x \geq 1. In these cases, the total-area condition involves an improper integral:

∫1∞4x3 dx=lim⁡t→∞∫1t4x−3 dx\int_1^{\infty} \frac{4}{x^3}\, dx = \lim_{t \to \infty} \int_1^{t} 4x^{-3}\, dx

provided the limit exists and equals 1.


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