CAIE A-Level · Mathematics 9709 · Probability

Exclusive and Independent Events (9709 PS1 – 5.3)

9 min readSyllabus 5.3PreviewBy Uzair Khan

Syllabus objective

Understand the meaning of exclusive and independent events, including determination of whether events A and B are independent by comparing the values of P(A ∩ B) and P(A) × P(B).

Introduction

Two of the most important relationships between events in probability are mutual exclusivity and independence. Both concepts appear frequently in 9709 PS1 questions — sometimes a question asks you to test whether a given relationship holds, and sometimes it assumes one and asks you to find a probability. Confusing the two is one of the most penalised errors in this paper, so understanding each precisely is essential.


Core Concept

Mutually Exclusive Events

Two events AA and BB are mutually exclusive (also called exclusive) if they cannot both occur at the same time. In set notation, their intersection is empty:

P(AB)=0P(A \cap B) = 0

On a Venn diagram the two circles do not overlap. Because they share no outcomes, the addition rule simplifies to:

P(AB)=P(A)+P(B)P(A \cup B) = P(A) + P(B)

Key idea: If one event happens, the other is impossible.

Independent Events

Two events AA and BB are independent if the occurrence of one gives no information about whether the other occurs — knowing AA happened does not change the probability of BB, and vice versa.

The formal test for independence is:

P(AB)=P(A)×P(B)P(A \cap B) = P(A) \times P(B)

If this equation holds, AA and BB are independent; if it fails, they are dependent.

This links directly to conditional probability (a prerequisite idea): AA and BB are independent if and only if P(AB)=P(A)P(A \mid B) = P(A) and P(BA)=P(B)P(B \mid A) = P(B), but the 9709 syllabus tests independence by comparing P(AB)P(A \cap B) with P(A)×P(B)P(A) \times P(B) — that is the required method.

The Crucial Distinction

PropertyConditionVenn overlapCan both occur?
Mutually exclusiveP(AB)=0P(A \cap B) = 0No overlapNo
IndependentP(AB)=P(A)×P(B)P(A \cap B) = P(A) \times P(B)Generally overlappingYes (unless one has probability 0)

Two non-trivial events cannot be both mutually exclusive AND independent. If P(AB)=0P(A \cap B) = 0 but P(A)>0P(A) > 0 and P(B)>0P(B) > 0, then P(A)×P(B)>00P(A) \times P(B) > 0 \neq 0, so independence fails.


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