CAIE A-Level · Mathematics 9709 · Momentum

Conservation of Momentum (9709 Mechanics 4.3)

9 min readSyllabus 4.3PreviewBy Uzair Khan

Syllabus objective

Use conservation of linear momentum to solve problems that may be modelled as the direct impact of two bodies, including direct impact of two bodies where the bodies coalesce on impact. Knowledge of impulse and the coefficient of restitution is not required.

Introduction

Conservation of linear momentum is one of the most powerful principles in mechanics. It allows us to find unknown velocities after a collision without needing to know anything about the forces acting during the impact — only the masses and velocities before and after matter. In the 9709 exam, questions on this topic typically ask you to find a velocity after a direct collision, determine a mass, or decide the direction of motion of a body after impact. Coalescence (where two bodies stick together and move as one) is a particularly common scenario worth mastering.


Core Concept

The Principle of Conservation of Linear Momentum states:

When no external force acts on a system of bodies along a given line, the total linear momentum of the system is constant.

In a direct impact (head-on collision along a straight line), the two bodies exert equal and opposite forces on each other (Newton's Third Law) for the same duration. These internal forces cancel out, so the total momentum is conserved.

Momentum is a vector quantity — direction matters. We always set a positive direction at the start and treat velocities in the opposite direction as negative.

For two bodies colliding directly:

Total momentum before=Total momentum after\text{Total momentum before} = \text{Total momentum after}
m1u1+m2u2=m1v1+m2v2m_1 u_1 + m_2 u_2 = m_1 v_1 + m_2 v_2

where m1,m2m_1, m_2 are masses and u1,u2u_1, u_2, v1,v2v_1, v_2 are velocities before and after the collision respectively.

Coalescence: If the two bodies stick together on impact, they move with a single common velocity VV after the collision:

m1u1+m2u2=(m1+m2)Vm_1 u_1 + m_2 u_2 = (m_1 + m_2)V

The number of unknowns reduces to one, making these the most straightforward collision problems.


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Prerequisites: Linear Momentum

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