CAIE A-Level · Mathematics 9709 · Integration

Integration Using Trigonometric Identities

8 min readPreviewBy Uzair Khan

What you'll be able to do

Use trigonometric relationships in carrying out integration, e.g. use of double-angle formulae to integrate sin²x or cos²(2x).

Introduction

Many trigonometric integrals — such as ∫sin⁡2x dx\int \sin^2 x \, dx or ∫cos⁡2(2x) dx\int \cos^2(2x) \, dx — cannot be evaluated directly from the standard forms table. However, by applying trigonometric identities, particularly the double-angle formulae, these expressions can be rewritten as standard integrals that are straightforward to evaluate.

This technique is explicitly required by the 9709 syllabus (ref 3.5) and appears regularly in Paper 3 examination questions, both as standalone integration tasks and as part of longer problems involving area, volume of revolution, or differential equations.


Core Concept

The central idea is to replace an integrand that cannot be integrated directly with an equivalent expression that can, using a known trigonometric identity.

The key identities used are the double-angle formulae for cosine, rearranged to express sin⁡2θ\sin^2\theta and cos⁡2θ\cos^2\theta in terms of cos⁡(2θ)\cos(2\theta):

cos⁡(2θ)=1−2sin⁡2θ  ⟹  sin⁡2θ=1−cos⁡(2θ)2\cos(2\theta) = 1 - 2\sin^2\theta \implies \sin^2\theta = \frac{1 - \cos(2\theta)}{2}
cos⁡(2θ)=2cos⁡2θ−1  ⟹  cos⁡2θ=1+cos⁡(2θ)2\cos(2\theta) = 2\cos^2\theta - 1 \implies \cos^2\theta = \frac{1 + \cos(2\theta)}{2}

These identities lower the power of the trigonometric function from 2 to 1, making the integral tractable. The same principle extends to expressions like sin⁡2(3x)\sin^2(3x) or cos⁡2 ⁣(x2)\cos^2\!\left(\tfrac{x}{2}\right) — simply replace θ\theta with the argument in question.

Other identities that appear in this context include:

  • sin⁡(2θ)=2sin⁡θcos⁡θ\sin(2\theta) = 2\sin\theta\cos\theta, used to integrate products sin⁡θcos⁡θ\sin\theta\cos\theta.
  • sin⁡2θ+cos⁡2θ=1\sin^2\theta + \cos^2\theta = 1, used to convert between powers.
  • 1+tan⁡2θ=sec⁡2θ1 + \tan^2\theta = \sec^2\theta, used to integrate tan⁡2θ\tan^2\theta.

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