CAIE A-Level · Mathematics 9709 · Functions

Graphs of Functions and Their Inverses (Pure Mathematics 1 – 9709)

10 min readSyllabus 1.2PreviewBy Uzair Khan

Syllabus objective

Illustrate in graphical terms the relation between a one-one function and its inverse (sketches should include an indication of the mirror line y = x).

Introduction

When a one-one function ff has an inverse f1f^{-1}, the two functions share a precise and beautiful graphical relationship: the graph of f1f^{-1} is the reflection of the graph of ff in the line y=xy = x. This is a core examiner expectation in 9709 — you will be asked to sketch inverse functions on the same axes as the original, always indicating the mirror line y=xy = x. Understanding this geometrically reinforces the algebraic definition of an inverse and is essential for interpreting domain and range restrictions visually.


Core Concept

Why reflection in y=xy = x?

If the point (a,b)(a, b) lies on the graph of ff, then f(a)=bf(a) = b, which means f1(b)=af^{-1}(b) = a. So the point (b,a)(b, a) lies on the graph of f1f^{-1}.

The transformation that swaps the coordinates of every point — sending (a,b)(b,a)(a, b) \mapsto (b, a) — is precisely a reflection in the line y=xy = x.

This means:

  • Every point on ff has a mirror image on f1f^{-1} across y=xy = x.
  • The line y=xy = x itself is the axis of symmetry between the two curves.
  • If a point lies on y=xy = x (i.e. a=ba = b), it maps to itself — it is a fixed point of the reflection.

The one-one condition

Only a one-one (injective) function has an inverse that is itself a function. Graphically, a function is one-one if and only if every horizontal line intersects its graph at most once (the horizontal line test). If a function fails this test, its domain must be restricted to a suitable interval before an inverse can be drawn.

Domain and range swap

When ff has domain AA and range BB:

  • f1f^{-1} has domain BB and range AA.

On a graph, this swap is visible: the xx-extent of the inverse curve equals the yy-extent of the original, and vice versa.


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Prerequisites: Inverse Functions

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