CAIE A-Level · Mathematics 9709 · Functions

Composite Functions — Pure Mathematics 1 (9709)

8 min readSyllabus 1.2PreviewBy Uzair Khan

Syllabus objective

Identify the range of a given function in simple cases, and find the composition of two given functions (including the condition that a composite function gf can only be formed when the range of f is within the domain of g).

Introduction

Composite functions arise whenever one function is applied after another — a situation that appears throughout Pure Mathematics and beyond. In 9709 Paper 1, questions on composite functions regularly ask you to form gf(x)gf(x), state its domain and range, or determine whether a composition is valid at all. Mastery of this topic requires precise understanding of domain and range, and a careful eye for the condition that governs when a composition is permitted.


Core Concept

What is a Composite Function?

Given two functions ff and gg, the composite function gfgf (read "g of f") means: apply ff first, then apply gg to the result.

gf(x)=g(f(x))gf(x) = g\bigl(f(x)\bigr)

The output of ff becomes the input of gg. This is the key insight that drives everything else.

Order matters. In general, gffggf \neq fg. Always apply the function nearest to xx first.

The Existence Condition

The composite gfgf can only be formed when:

Range of fDomain of g\text{Range of } f \subseteq \text{Domain of } g

That is, every value that ff can output must be a valid input for gg. If even one value in the range of ff falls outside the domain of gg, the composition gfgf is not defined.

Domain and Range of a Composite Function

Once gfgf is valid:

  • The domain of gfgf is the domain of ff (since ff is applied first).
  • The range of gfgf is found by tracing what happens to the range of ff through gg, or by analysing gf(x)gf(x) directly.

Identifying the Range in Simple Cases

For standard functions:

Function typeRange (typical)
f(x)=x2f(x) = x^2 with domain R\mathbb{R}f(x)0f(x) \geq 0
f(x)=x2f(x) = x^2 with domain x2x \geq 2f(x)4f(x) \geq 4
f(x)=xf(x) = \sqrt{x} with domain x0x \geq 0f(x)0f(x) \geq 0
f(x)=1xf(x) = \frac{1}{x}, x>0x > 0f(x)>0f(x) > 0
f(x)=2x+1f(x) = 2x + 1, xRx \in \mathbb{R}f(x)Rf(x) \in \mathbb{R}
f(x)=(x1)2+3f(x) = (x-1)^2 + 3, x1x \geq 1f(x)3f(x) \geq 3

Sketching or completing the square are standard tools for identifying ranges on the 9709 paper.


Unlock the full Functions note with Nova

You're reading the preview. Unlock the complete note — every worked example, examiner pitfall and practice question — plus 24/7 AI tutoring from Nova that teaches directly from these notes.

Keep learning

Explore CAIE A-Level Mathematics tutoring →

View the full Mathematics syllabus →

Part of Novark's free CAIE A-Level Mathematics notes