CAIE A-Level · Mathematics 9709 · Coordinate Geometry

Equation of a Circle — CAIE A-Level Pure Mathematics 1 (9709)

8 min readSyllabus 1.3PreviewBy Uzair Khan

Syllabus objective

Understand that the equation (x − a)² + (y − b)² = r² represents the circle with centre (a, b) and radius r (including use of the expanded form x² + y² + 2gx + 2fy + c = 0).

Introduction

The equation of a circle is a core topic in the Coordinate Geometry unit of Pure Mathematics 1. It connects the geometric definition of a circle (all points at a fixed distance from a centre) directly to algebra. In 9709 examinations, questions on circles appear regularly and often combine with straight-line work — for example, finding tangents, normals, or points of intersection. Mastering both standard forms and the ability to switch between them is essential for full marks.


Core Concept

The Geometric Definition

A circle is the locus of all points that are a fixed distance rr (the radius) from a fixed point (a,b)(a, b) (the centre).

If a general point (x,y)(x, y) lies on the circle, then by the distance formula:

(xa)2+(yb)2=r\sqrt{(x-a)^2 + (y-b)^2} = r

Squaring both sides gives the standard equation.

Form 1 — Centre–Radius Form

(xa)2+(yb)2=r2\boxed{(x - a)^2 + (y - b)^2 = r^2}

This form immediately reveals the centre (a,b)(a, b) and radius rr.

Sign convention: The centre coordinates appear with the opposite sign inside the brackets. The centre of (x3)2+(y+2)2=25(x-3)^2 + (y+2)^2 = 25 is (3,2)(3, -2), not (3,2)(-3, 2).

Form 2 — Expanded (General) Form

Expanding Form 1 and rearranging yields the general form:

x2+y2+2gx+2fy+c=0\boxed{x^2 + y^2 + 2gx + 2fy + c = 0}

Here the centre is (g,f)(-g, -f) and the radius is r=g2+f2cr = \sqrt{g^2 + f^2 - c}, provided g2+f2c>0g^2 + f^2 - c > 0.

The two forms are entirely equivalent; the choice of which to use depends on what information is given or required.


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