CAIE A-Level · Mathematics 9709 · Algebra

Partial Fractions (Pure Mathematics 3 – 9709)

10 min readSyllabus 3.1PreviewBy Uzair Khan

Syllabus objective

Recall an appropriate form for expressing rational functions in partial fractions, and carry out the decomposition, in cases where the denominator is no more complicated than (ax + b)(cx + d)(ex + f), (ax + b)(cx + d)², or (ax + b)(cx² + d). Excluding cases where the degree of the numerator exceeds that of the denominator.

Introduction

Partial fractions is the process of splitting a single rational function into a sum of simpler fractions. In 9709 Paper 3, partial fractions appear as a standalone skill and as an essential tool for integration, binomial expansions of rational functions, and inverse Laplace transforms in further work. Mastering the correct form for each denominator type is the key examiner requirement — an incorrect form scores zero, however much algebra follows.

The syllabus restricts the cases to:

  1. Distinct linear factors: denominator of the form (ax+b)(cx+d)(ex+f)(ax+b)(cx+d)(ex+f)
  2. Repeated linear factor: denominator of the form (ax+b)(cx+d)2(ax+b)(cx+d)^2
  3. Irreducible quadratic factor: denominator of the form (ax+b)(cx2+d)(ax+b)(cx^2+d)

In all cases the degree of the numerator must be strictly less than the degree of the denominator (proper fraction). If it is not, you must first perform polynomial division — but the syllabus explicitly excludes that situation from this objective, so every exam question here will already be a proper fraction.


Core Concept

A rational function is f(x)g(x)\dfrac{f(x)}{g(x)} where ff and gg are polynomials. When deg(f)<deg(g)\deg(f) < \deg(g) the fraction is proper and can be decomposed into partial fractions whose denominators are the individual factors of g(x)g(x).

Why does this work? Every real polynomial factors into linear and irreducible quadratic factors over R\mathbb{R}. Each such factor contributes a term (or terms, for repeated factors) to the partial fraction decomposition. The constants in the numerators of those terms are uniquely determined — that uniqueness is what makes the method valid.

Choosing the correct form

Denominator typeCorrect partial fraction form
(ax+b)(cx+d)(ex+f)(ax+b)(cx+d)(ex+f) — three distinct linear factorsAax+b+Bcx+d+Cex+f\dfrac{A}{ax+b}+\dfrac{B}{cx+d}+\dfrac{C}{ex+f}
(ax+b)(cx+d)2(ax+b)(cx+d)^2 — one linear, one repeated linearAax+b+Bcx+d+C(cx+d)2\dfrac{A}{ax+b}+\dfrac{B}{cx+d}+\dfrac{C}{(cx+d)^2}
(ax+b)(cx2+d)(ax+b)(cx^2+d) — one linear, one irreducible quadraticAax+b+Bx+Ccx2+d\dfrac{A}{ax+b}+\dfrac{Bx+C}{cx^2+d}

Critical rule for the quadratic factor: the numerator over cx2+dcx^2+d must be linear (Bx+CBx+C), not a single constant. This is the most common mark-losing error.


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